转载统计数中二进制1的个数

#include<stdio.h>
int main()
{
	int a;
	int b[1000],i,x0,x1,k,c;
	x0=0;
	x1=1;
	printf("请输入十进制数a\n");
	scanf("%d",&a);
	if(a == 0)
	{
		printf("十进制数0转成二进制数为0\n");
		printf("1的个数为0\n");
		printf("0的个数为1\n");

	}
	
	c = a;
	for(i=0;i<1000;i++)
		b[i]=0;
     i=0;
	while(a!=1)
	{
		b[i]=a%2;
		a=a/2;
		i++;
	}
    k=i-1;
	printf("十进制数%d转成二进制数为%d",c,a);
	for(i=k;i>=0;i--)
		printf("%d",b[i]);
	printf("\n");
	for(i=0;i<=k;i++)
	{
		if(b[i]==0)
			x0++;
		else
			x1++;
	}
	printf("0的个数为%d\n",x0);
	printf("1的个数为%d\n",x1);
	return 0;
}
VC上调试成功

===================================================

#include "stdio.h"
int main()
{
int number,i=7,b[8]={0},m=0,n=0;
printf("Input a number between 0 and 255:");
scanf("%d",&number);
while(number)
{
b[i]=number%2;
number/=2;
if(b[i]==0)
M++;
IF(B[i]==1)
n++;
i--;
}
for(i=1;i<8;i++)
{
printf("%d,%d,%d",b[i],m,n);
}printf("\n");
}