异常处理之：如何让Python直接告诉我们异常的原因？

try:

open("abc.txt",'r')

print (aa)

except Exception as msg:    #或者写成except BaseException as msg: 定义了msg变量用于接收 print (msg)      #异常信息，并通过print将其打印出来

运行结果：

======================= RESTART: D:\Pythonwork\test.py =======================

[Errno 2] No such file or directory: 'abc.txt'

>>>