在这fiddle行27中显示
var doctors = [
new Doctor("Doc A","A1"),
new Doctor("Doc B","A1"),
new Doctor("Doc C","A3")
];
在这里,Doc A,Doc B和Doc C是硬编码的.它们也是Knockout绑定:
ko.applyBindings(
new Patient("idValue", "nameValue", "addressValue", "Female", "usernameValue",
"passwordValue", "emailValue", "mobileValue", "imgFileValue",
"imgSrcValue", "imagePathValue", "useridValue", "A3")
);
无论通过a1,a2还是a3,都会选择相应的doc.例如,我在绑定中传递a3,因此我选择了Doc C.
鉴于此JSON:
{
"doctors": [
{
"id": 8,
"schedules": [
{
"id": 8,
"totime": "11:17",
"dayId": 2,
"location": "Somajiguda",
"fromtime": "10:17",
"hospitalId": 5,
"day": "Tuesday",
"hospital": "Yashoda"
}
],
"username": "d1",
"degree": "DA(Anaesthesia)",
"email": "1@2.com",
"imagePath": "",
"department": "Bio-Chemistry",
"name": "d1",
"userid": 51,
"gender": "Male",
"mobile": "1234567900"
},
{
"id": 10,
"schedules": [
{
"id": 10,
"totime": "12:35",
"dayId": 2,
"location": "Somajiguda",
"fromtime": "11:35",
"hospitalId": 5,
"day": "Tuesday",
"hospital": "Yashoda"
}
],
"username": "d3",
"degree": "BDS",
"email": "d3@d3.com",
"imagePath": "",
"department": "Bio-Chemistry",
"name": "d3",
"userid": 56,
"gender": "Male",
"mobile": "1234567890"
},
{
"id": 1,
"schedules": [
{
"id": 1,
"totime": "12:55",
"dayId": 1,
"location": "Somajiguda",
"fromtime": "11:55",
"hospitalId": 5,
"day": "Monday",
"hospital": "Yashoda"
}
],
"username": "doctor",
"degree": "BDS",
"email": "",
"imagePath": null,
"department": "Critical Care",
"name": "doctor",
"userid": 4,
"gender": "Male",
"mobile": "1234567890"
},
{
"id": 7,
"schedules": [
{
"id": 7,
"totime": "11:17",
"dayId": 2,
"location": "Somajiguda",
"fromtime": "11:17",
"hospitalId": 5,
"day": "Tuesday",
"hospital": "Yashoda"
}
],
"username": "donald",
"degree": "DA(Anaesthesia)",
"email": "donald@doctor.com",
"imagePath": "",
"department": "Bio-Chemistry",
"name": "donald",
"userid": 47,
"gender": "Male",
"mobile": "1234567989"
},
{
"id": 6,
"schedules": [
{
"id": 6,
"totime": "11:15",
"dayId": 1,
"location": "Somajiguda",
"fromtime": "11:15",
"hospitalId": 5,
"day": "Monday",
"hospital": "Yashoda"
}
],
"username": "john",
"degree": "BDS",
"email": "john@john.com",
"imagePath": null,
"department": "Anesthesiology",
"name": "john",
"userid": 46,
"gender": "Male",
"mobile": "1234567890"
},
{
"id": 5,
"schedules": [
{
"id": 5,
"totime": "13:11",
"dayId": 2,
"location": "Somajiguda",
"fromtime": "12:11",
"hospitalId": 5,
"day": "Tuesday",
"hospital": "Yashoda"
}
],
"username": "sknayak",
"degree": "BDS",
"email": "sknayak@sknayak.com",
"imagePath": "",
"department": "Anesthesiology",
"name": "sknayak",
"userid": 38,
"gender": "Male",
"mobile": "1234567890"
},
{
"id": 2,
"schedules": [
{
"id": 2,
"totime": "16:26",
"dayId": 6,
"location": "Somajiguda",
"fromtime": "15:26",
"hospitalId": 5,
"day": "Saturday",
"hospital": "Yashoda"
}
],
"username": "drsukant",
"degree": "BDS",
"email": "",
"imagePath": null,
"department": "Anesthesiology",
"name": "sukant",
"userid": 9,
"gender": "Male",
"mobile": "1234567890"
}
]
}
获得GET请求:
$.ajax({
type: "GET",
url: projectUrl "getDoctors",
dataType:"json",
jsonp: true,
async:false ,
success: function (data) {
$.each(data.doctors, function(index, currPat) {
console.log(currPat.username);
});
}
});
我想要来自JSON的用户名和ID代替’Doc A’,’a1′,’Doc B’,’a2’等…作为var doctors = ….的替代品
在我的AJAX成功中,我试过:
success: function (data) {
$.each(data.doctors, function(index, currPat) {
new Doctors(currPat.id,currPat.username);
});
}
解决方法: 可能是这样的?
var doctors = [];
$.ajax({
type: "GET",
url: projectUrl "getDoctors",
dataType:"json",
jsonp: true,
async:false ,
success: function (data) {
$.each(data.doctors, function(index, currPat) {
doctors.push[currPat.id,currPat.username];
});
}
});
你的最终结果应该是这样的:
doctors = [[id1,name1],[id2,name2], ...... [id10,name10]]
或者您也可以使用以下格式:
doctors.push({id:currPat.id,name:currPat.username});
然后你的最终结果应该是这样的:
doctors = [{id:id1,name:name1},{id:id2,name:name2},......,{id:id10,name:name10}]
*我个人更喜欢格式2
编辑使用JQuery,.map()
var doctors;
$.ajax({
type: "GET",
url: projectUrl "getDoctors",
dataType:"json",
jsonp: true,
async:false ,
success: function (data) {
doctors = $.map(function () {
return [data.id,data.username];}).get();
}
});
比上面提到的稍微短一点. 来源:https://www./content-1-264301.html
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