import randomattr = ["烂头", "枪", "虎", "人", "鸡", "蜂"] attr1 = attr * 4 # 每种角色四个 person1_list = [] person2_list = [] for i in range(0, int(len(attr1) / 2)): # 两个人平分 x = random.choice(attr1) person1_list.append(x) attr1.remove(x) y = random.choice(attr1) person2_list.append(y) print("初始牌组随机选择完成：") print("person1初始牌组：",end=") print(person1_list) print("person2初始牌组：",end=") print(person2_list) count = 1 while 1: print("--------------------------------") print("第{}轮".format(count)) print("--------------------------------") x = random.choice(person1_list) # 1出牌,随机选择牌 y = random.choice(person2_list) # 2出牌,随机选择牌 print("person1出牌{}".format(x)) print("person2出牌{}".format(y)) x_int = attr.index(x) # x的索引 y_int = attr.index(y) # y的索引 # print(x_int) # print(y_int) ’’’ 逻辑如下： x==y 即出牌一致，两人弃牌 (x_int - y_int == -1) or x_int - y_int == 5 1赢，收2牌 2赢，收1牌 两人出牌没有关联，弃牌 ’’’ if x == y: # 一致则放至牌堆 print("两人出牌一致，都是{}，弃牌".format(x)) person1_list.remove(x) person2_list.remove(y) print("person1牌组：", end=") print(person1_list) print("person2牌组：", end=") print(person2_list) elif (x_int - y_int == -1) or x_int - y_int == 5: # 1赢 person1_list.append(y) # 1收牌 person2_list.remove(y) # 2弃牌 完成逻辑2牌给1 print("person1赢,收牌,现在牌组为：", end=") print(person1_list) print("person2牌组为：", end=") print(person2_list) elif (y_int - x_int == -1) or y_int - x_int ==5: # 2赢 person2_list.append(x) # 同上 person1_list.remove(x) print("person2赢,收牌,现在牌组为：", end=") print(person2_list) print("person1牌组为：", end=") print(person1_list) else: # 其它情况也弃牌 print("不输不赢，弃牌") person1_list.remove(x) person2_list.remove(y) print("person1牌组：", end=") print(person1_list) print("person2牌组：", end=") print(person2_list) if len(person1_list) == 0 or len(person2_list) == 0: print("游戏结束", end=") print("--------------------------------") if len(person1_list) == 0: print("person2赢,最终牌组为", end=") print(person2_list) break else: print("person1赢,最终牌组为", end=") print(person1_list) break count += 1 | 
