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猜想等号成立条件,调整构造证明不等式
2014-07-06 | 阅:  转:  |  分享 
  
6–202008AFBI6BA

C5C6“C7C8C9CAC3CB”CCCDATAUCEC7ALCFCG

BGBCBCBCBGBJCQBXB6B7B8AGBZAGBBCRCSCTAFAGAGACBEBCBCBJCUAHAIBDB2CPCV

AHAIA4BVBWA2?A3B6:“AHAIB0BXBYCXCYASBZ

AOCUC0DGC1B0BXBYCXCYAVB2,BPCSB7AVBUBOAXBB

C2,C3C2C4BDACC5D3CPC9BUBOAXB0B1B2,BPC6C7

BXCPCID8CSB7BBC2,C8C2DHC9CAB4ACC6CBACCCCS

AGD7CPB0C4BD.”BPBQAHAIC4BDDHAKDEAHAICDDF

B0AVA4CEAIBZCR,CDA1C9DEAHAIC5CFB0AVA4ATB8

C0AH,B1ASAHAIC4BDAPB0A4A4CGCHCIDECHA5CWAB

D7CJA7CKCQA6B0CLCM.A6AFC3BHAVBUDHBLAHB0

CSB7D7D8.

CN1B9aACb∈R

+

,CSB7:

a

2

b

+

b

2

a

greaterorequalslanta+b.

CSB7:?BBCNBGDHBLAHCGC2

a

2

b

+bgreaterorequalslant2a,

b

2

a

+agreaterorequalslant2b,A3DHBLAHCABFCGCSCP

a

2

b

+

b

2

a

greaterorequalslanta+b.

AVBVCOBCC8C4BD:(1)BLCPAOBSB0B5C0DEa=

b,C4CSB7CHCQCRDE?(2)B9CHaACbACc∈R

+

,AT

BDC2DJCSB2B0DHBLAH?

DDCN1BNCPC4BDB0DHBLAH:

a

2

b

+

b

2

c

+

c

2

a

greaterorequalslanta+b+c;···················A1

a

2

b+c

+

b

2

c+a

+

c

2

a+b

greaterorequalslant

a+b+c

2

.·····A2

C4CCBIAVBUDHBLAHCTCUCN1B0BZCRCGBNCPCV

CWB0CSB7,CXB8CZAYBIAKBUDHBLAHB0CSB7,CGB8

BBC2AMB0CSB7BZCRCY?CWABDHCZALAVAF.

CUBQC3C4CNBGDHBLAHCGC2A6AFD5BUDHBLAH:

a

2

b+c

+(b+c)greaterorequalslant2a,

b

2

c+a

+(c+a)greaterorequalslant2b,

c

2

a+b

+(a+b)greaterorequalslant2c.

D5AHCABFC2

a

2

b+c

+

b

2

c+a

+

c

2

a+b

greaterorequalslant0,

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B7D4D5?CUB9C5B8CAB4AVAFCSB7CXCYAP,BLCPAO

BSB0B5C0BTCGA6DDC9CPAB,BGBQa=b+c,b=

c+a,c=a+bB1ASAOBSC5CHDEa=b=c=

0,ASA6CKDHD6.D3BPCWABC5B8CCCSAVAFCSB7,D7

a=b=c>0AOBSA0CG.CSD8DAAF:

a

2

b+c

+

b+c

4

greaterorequalslanta,

b

2

c+a

+

c+a

4

greaterorequalslantb,

c

2

a+b

+

a+b

4

greaterorequalslantc,

D5AHCABFC2

a

2

b+c

+

b

2

c+a

+

c

2

a+b

greaterorequalslant

a+b+c

2

,

BDB0CAB4AVAFBLCPAOBSB0B5C02a=b+c,2b=

c+a,2c=a+b,BGBQCGA6C1a=b=c>0AO

BS.C3C4A6BSD9B4,DADBC4BDCSB7:B9aACbACcAC

d>0,AJ

a

2

b+c+d

+

b+c+d

9

greaterorequalslant

2a

3

,

b

2

a+c+d

+

a+c+d

9

greaterorequalslant

2b

3

,

c

2

a+b+d

+

a+b+d

9

greaterorequalslant

2c

3

,

d

2

a+b+c

+

a+b+c

9

greaterorequalslant

2d

3

,BTAHCABFCGC2

AVDHBLAH

a

2

b+c+d

+

b

2

a+c+d

+

c

2

a+b+d

+

d

2

a+b+c

greaterorequalslant

a+b+c+d

3

(BLCPAOBSB5C0a=

b=c=d>0).···········································A3

C3C4A1ACA2ACA3DHBLAH,CWABCGA6BNCPBE

AVCTB0C4BD:B9x

1

,x

2

,···,x

n

∈R

+

,A1x

1

+

x

2

+···+x

n

=a,CGC2CP

x

2

1

a?x

1

+

x

2

2

a?x

2

+

···+

x

2

n

a?x

n

greaterorequalslant

a

n?1

(BLCPAOBSB5C0x

1

=x

2

=

···=x

n

>0).············································A4

CSB7:

x

2

1

a?x

1

+

a?x

1

(n?1)

2

greaterorequalslant

2x

1

n?1

,

x

2

2

a?x

2

2008AFBI6BA6–21

+

a?x

2

(n?1)

2

greaterorequalslant

2x

2

n?1

,···,

x

2

n

a?x

n

+

a?x

n

(n?1)

2

greaterorequalslant

2x

n

n?1

,nBUDHBLAHCABFCGCSB7DHBLAHA4,BLCP

AOBSB0B5C0x

1

=x

2

=···=x

n

>0.

BMCXA6BSB0C4BDCXCYC8CSB7D9B4,CWABC5D3

CGA6BPCSB7C2DCC3C4BDBLCPAOBSB0B5C0,BQBCC3

C4CNBGDHBLAH,DDBYCACCB0B6AHAJDEAHAH,B4BP

CSB7B0CXCYAPD8DFDGDHDHBLAHB0BLCPAOBS,DHBL

CPB0BZDIBYDJ,BTCGA6A0BBC9A4BZCRA7CKAVAWDH

BLAHB0CSB7CQA6AB.

CN2BXDGBYAHaACbAWAXa+b=1,BWCS:

(a+2)

2

+(b+2)

2

greaterorequalslant

25

2

.

A7A6CSCRB4CI,A1A2C5BBA6BSAGA3B9B0BCBD:

DD(a+2)

2

=(b+2)

2

=

25

4

C4BDBLCPAOBSB0B5

C0DEa=b=

1

2

.B4CSC4BDAOBS:?BBDHBLAH(a+

2)

2

+

25

4

greaterorequalslant5(a+2),B1AX(b+2)

2

+

25

4

greaterorequalslant5(b+

2),BLCPAOBSA4CBa=b=

1

2

,

A2(a+2)

2

+(b+2)

2

+

25

2

greaterorequalslant5(a+b+4)=

25,CGCSC2(a+2)

2

+(b+2)

2

greaterorequalslant

25

2

.

CN3(1990AFBI1A5“A6A7A8”)BXDGxACyAC

z>0,B4A1

x

2

1+x

2

+

y

2

1+y

2

+

z

2

1+z

2

=2,BW

CS:

x

1+x

2

+

y

1+y

2

+

z

1+z

2

lessorequalslant



2.

CSB7:C4BDBLCPAOBSB0B5C0A5x=y=z=



2.

A1

x

2

1+x

2

+

y

2

1+y

2

+

z

2

1+z

2

=2

??

1

1+x

2

+

1

1+y

2

+

1

1+z

2

=1,

A1

x

1+x

2

=



2

2



2x

1+x

2

lessorequalslant



2

2

?

?

?

2+x

2

2

1+x

2

?

?

?

=



2

4

parenleftbigg

1+

1

1+x

2

parenrightbigg

(BKASBLCPAOBSB5C0x=



2).

B1AXCGC2

y

1+y

2

lessorequalslant



2

4

parenleftbigg

1+

1

1+y

2

parenrightbigg

,

z

1+z

2

lessorequalslant



2

4

parenleftbigg

1+

1

1+z

2

parenrightbigg

.

AUD5BUDHBLAHCABFC2

x

1+x

2

+

y

1+y

2

+

z

1+z

2

lessorequalslant



2

4

parenleftbigg

3+

1

1+x

2

+

1

1+y

2

+

1

1+z

2

parenrightbigg

=



2(DGDHBLCPAOBS).

CN4(BI36A5IMOALA6)D9aACbACc>0,A1

abc=1,BWCS:

1

a

3

(b+c)

+

1

b

3

(c+a)

+

1

c

3

(a+b)

greaterorequalslant

3

2

.

CSB7:C4BDBLCPAOBSB0B5C0A5a=b=c=

1.

1

a

3

(b+c)

+

1

b

3

(c+a)

+

1

c

3

(a+b)

greaterorequalslant

3

2

??

bc

a

2

(b+c)

+

ca

b

2

(c+a)

+

ab

c

2

(a+b)

greaterorequalslant

3

2

.

C3C4CNBGDHBLAHCGC2

bc

a

2

(b+c)

+

b+c

4bc

greaterorequalslant

1

a

,

ca

b

2

(c+a)

+

c+a

4ca

greaterorequalslant

1

b

,

ab

c

2

(a+b)

+

a+b

4ab

greaterorequalslant

1

c

.

BLCPAOBSB0B5C0A52bc=ab+ca,2ca=bc+ab,

2ab=ca+bc,D5AHB1ASAOBSCHa=b=c=1.

AUD5BUDHBLAHCABFC2

bc

a

2

(b+c)

+

ca

b

2

(c+a)

+

ab

c

2

(a+b)

+

a+b

4ab

+

c+a

4ca

+

b+c

4bc

greaterorequalslant

1

a

+

1

b

+

1

c

,

A0

bc

a

2

(b+c)

+

ca

b

2

(c+a)

+

ab

c

2

(a+b)

+

c(a+b)

4

+

b(c+a)

4

+

a(b+c)

4

greaterorequalslantbc+ca+ab,

A2

bc

a

2

(b+c)

+

ca

b

2

(c+a)

+

ab

c

2

(a+b)

greaterorequalslant

1

2

(bc+ac+ab)greaterorequalslant

3

2

3



a

2

b

2

c

2

=

3

2

(DGDH

BLCPAOBS).

AGA6BMDHBLAHAOBS.

CN5(2005AFAPA9A9BWAAAAABCHALA6)D9

aACbACc>0,ab+bc+ca=

1

3

,BWCS:

1

a

2

?bc+1

+

1

b

2

?ca+1

+

1

c

2

?ab+1

lessorequalslant3.

CSB7:C4BDBLCPAOBSB0B5C0A5

a=b=c=

1

3

.

A1a

2

?bc+1=a

2

?bc+3(ab+bc+ca)=

a(a+b+c)+

2

3

,APq=a+b+c,

1

a

2

?bc+1

+

1

b

2

?ca+1

+

1

c

2

?ab+1

6–222008AFBI6BA

=

1

aq+

2

3

+

1

bq+

2

3

+

1

cq+

2

3

=

3

3aq+2

+

3

3bq+2

+

3

3cq+2

,

A2

3

3aq+2

+

3

3bq+2

+

3

3cq+2

lessorequalslant3

??

3aq

3aq+2

+

3bq

3bq+2

+

3cq

3cq+2

greaterorequalslant1(BL

CPAOBSB5C0a=b=c=

1

3

A1q=1).

C3C4CNBGDHBLAH

3aq

3aq+2

+

aq(3aq+2)

3

greaterorequalslant

2aq(DGCSaq=

1

3

ASBLCPAOBS).

B1AXCGC2CP

3bq

3bq+2

+

bq(3bq+2)

3

greaterorequalslant2bq,

3cq

3cq+2

+

cq(3cq+2)

3

greaterorequalslant2cq,(bq=cq=aq,B1ASD6AUBL

CPAOBSB0B5C0),AGA6D5BUDHBLAHCABFC2

3aq

3aq+2

+

3bq

3bq+2

+

3cq

3cq+2

greaterorequalslantaq

parenleftbigg

4?3aq

3

parenrightbigg

+bq

parenleftbigg

4?3bq

3

parenrightbigg

+cq

parenleftbigg

4?3cq

3

parenrightbigg

=

q

2

[4?3(a

2

+b

2

+c

2

)]

3

=

q

2

3

parenleftbigg

4?3

parenleftbigg

q

2

?

2

3

parenrightbiggparenrightbigg

=q

2

(2?q

2

)

=?(q

2

?1)

2

+1.

B7?(q

2

?1)

2

+1lessorequalslant1,BQBKCSB7ACAD.

A6BSCSB7CXCYCJ?AWAXBLCPAOBSB5C0,B7AZ

DFCUCPD3AFC2CXCCAGB0AHAI,BKAS,CGBQCO?BB

AJAKB0DEAHAH,C1BBALAMDHBLAHDADBC6AOCSB7.

D9a

1

=

3aq

3aq+2

,b

1

=

aq(3aq+2)

3

,

a

2

=

3bq

3bq+2

,b

2

=

bq(3bq+2)

3

,

a

3

=

3cq

3cq+2

,b

3

=

cq(3cq+2)

3

.

A2(a

1

+a

2

+a

3

)(b

1

+b

2

+b

3

)

=

parenleftbigg

3aq

3aq+2

+

3bq

3bq+2

+

3cq

3cq+2

parenrightbigg

×

parenleftbigg

aq(3aq+2)

3

+

bq(3bq+2)

3

+

cq(3cq+2)

3

parenrightbigg

greaterorequalslant(



a

1

b

1

+



a

2

b

2

+



a

3

b

3

)

2

=(aq+bq+cq)

2

=q

4

.

BLCPAOBSB0B5C0

1

3aq+2

=

1

3bq+2

=

1

3cq+2

,

A0aq=bq=cq,CUAP

aq(3aq+2)

3

+

bq(3bq+2)

3

+

cq(3cq+2)

3

=

3(a

2

+b

2

+c

2

)q

2

+2(a+b+c)q

3

=

3

parenleftbigg

q

2

?

2

3

parenrightbigg

q

2

+2q

2

3

=q

4

A2

3aq

3aq+2

+

3bq

3bq+2

+

3cq

3cq+2

greaterorequalslant1.

BHA6BSB0CSB7CWABC5D3,ANBQ?BBAOD4DHBL

AHBPCSB7B0CXCYAPCHAVBOAPAQAZ,B7DEC3C4BLCP

AOBSB5C0C4DEAHAHB0AJAKC8ARAS,CUBQBPCSB7B0

CXCYAPBLDJCXB8BXBB.DACN5,CWABBPACADB0CN

ATBSDHBTBDB0AJAKCACCDEAHAH,BQCOC1BBALAMDH

BLAHBTCHDADBC6AOCSB7.

BMCXA6BSANCNCGA6C6CP,C4BDB4B4CSCPBLCP

AOBSB0B5C0DED0ATB8B0,B1ASC4DHBLAHB0AUBPC8

C0C8ASAX,A6AVBPCSB7CXCYAPB0ARAS,B4DGDHDH

BLAHB0BLCPAOBSDECSB7B0CCAW.BYDAAXAYAGAZ

BMB0“CGCHB0B1B0C4BD,BTCGCHB2B0B0C5D3”,AH

AIBWABC5D3AHAIB3B4B0CXCY,B5B5DEC3CHAVBUC4

BD,CDBCA0DEC4C4BDD8COB4CSAJCCBYB0CXCY.

B6B7B8B9

[1]BABBBCACBDBEBF.A2?A3BGBXBHA7.BIBJ

A4BVCPARBK.1998.

[2]BABLBMACBABNA2.AHAIC4BDB0CVBOACBZ

CRAVCUC4AHAIC5CFB0BPBQ.C6BRB0AIAIBS(CYBQ

CEAIAR).2007.6.

[[3]BABTBU.DDBYDIAYCSB7DHBLAH.AHAXCV

BR(A9APAR).2006.5.

[4]BVB7BWACBXBY.BBDIAYB1C2CRCSB7AVCV

BJAHDHBLAH.BZC0AXCEA4AICDDF.2007.1.A0A0

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

D1D2

BGAABI4BABI23B1D0ADAZ“BMCXA6BSCGCT,CG

A6C6CPBVACBRACAMACBP”BCAMD3C1“AGB0CCB6,B1

ASC9D8AVA4CZC1DJAHAGB0BGBCAVAHAIBCBDBZCR

B0BAD0.D5BUDGAHBJC1DECCCCnB0AVB0ACAKB0AC

D5B0B0D3AHCCB6,ASBPAGB0DHAHCAB1,A5AUD4D8

AVA4AIATAHAIDGC1ACBZCRAVA0BBAHAIBCBDB1BO

ABCNAT.”CMBKBEBY,B4DIBXA2ASBUA2CUD4.

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